The length of the tangent from any point on the circle to the circle `(x-3)^2 + (y + 2)^2 =5r^2` to the circle ` (x-3)^2 + (y + 2)^2 = r^2` is 4 units. Then the area between the circles is

The length of the tangent from any point on the circle to the circle `

1.	The length of the tangent from any point on the circle to the circle `(x-3)^2 + (y + 2)^2 =5r^2` to the circle ` (x-3)^2 + (y + 2)^2 = r^2` is 4 units. Then the area between the circles is
Answer» Correct Answer - `16 pi` From the figure, `5r^(2)=16+r^(2)` `:. R^(2)= 4` `:. R = 2` `:. ` Area between circles `=pi(5r^(2))=pi(r^(2))=4pir^(2)=16pi`

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The length of the tangent from any point on the circle to the circle `(x-3)^2 + (y + 2)^2 =5r^2` to the circle ` (x-3)^2 + (y + 2)^2 = r^2` is 4 units. Then the area between the circles is

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