the length of the rectangle twice of its breadth if its perimeter is 4

1.	the length of the rectangle twice of its breadth if its perimeter is 45cm,find the dimensions of the rectangle?
Answer» $\huge\underline\mathfrak\pink{Answer}$ Let meet of ratio of DIMENSIONS be x. Means length be 2X and Breadth be x. $\sf \dashrightarrow \: P=2(l+b) \\ \\\sf \dashrightarrow \: 45 \: m = 2(2x+x) \\ \\ \sf \dashrightarrow \:45 \: m = 2 \times 3x \\ \\\sf \dashrightarrow \: 45 \: m = 6x \\ \\\sf \dashrightarrow \: \frac{45 \: m}{6} = x \\ \\ \sf \dashrightarrow \: \red{7.5 \: m}$ Hence length = 2 × 7.5 = 14.0 m = 14 m And Breadth = 1 × 7.5 m = 7.5 m. ㅤㅤㅤ $\sf \therefore \: Hence, \: the \: length \: of \: rectangle \: is \: \bold{ 14 \: m} \: and \: breadth \: is \: \bold{ 7.5 \: m. }$ ㅤㅤ $\rule{300px}{.8ex}$

the length of the rectangle twice of its breadth if its perimeter is 45cm,find the dimensions of the rectangle?

Answer»

$\huge\underline\mathfrak\pink{Answer}$

Let meet of ratio of DIMENSIONS be x.

Means length be 2X and Breadth be x.

$\sf \dashrightarrow \: P=2(l+b) \\ \\\sf \dashrightarrow \: 45 \: m = 2(2x+x) \\ \\ \sf \dashrightarrow \:45 \: m = 2 \times 3x \\ \\\sf \dashrightarrow \: 45 \: m = 6x \\ \\\sf \dashrightarrow \: \frac{45 \: m}{6} = x \\ \\ \sf \dashrightarrow \: \red{7.5 \: m}$