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The length of the cord of a circle is 16 cm and distance of cord from centerof the circle is 6 cm then findthe radius of circle. |
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Answer» AB is the cord. Join O with A and B. In ∆ OBM and ∆ OAM, i) Angle OMB = Angle OMA ( right ANGLES) ii) OB = OA ( radii) iii) OM = OM ( common side) So, ∆ OBM ≅ ∆ OAM (by RHS) By CPCT, i) AM = BM ii) AM = 8 cm iii) OM = 6 cm According to Pythagoras theorem, OA=√(OM^2+AM^2) cm =√(6^2+8^2) cm =√ 36+64 cm =√ 100 cm = 10 cm Hence, the RADIUS of circle is 10 cm. |
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