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The length of simple pendulum executing SHM is increased by `69%` The percentage increase in the time period of the pendulum isA. `30%`B. `11%`C. `21%`D. `42%` |
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Answer» Correct Answer - A `(T)/(T)=sqrt((169)/(100)), T=(13)/(10)T` `((T)/(T)-1)xx100%=((13)/(10)-1)xx100%=30%` |
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