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The length of a rectangle is greater than twice it's breadth by 1cm if it's breadth is doubled and length is decreased by 4 cm it's area remains the same find the dimensions |
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Answer» l=8 b=3.5 Step-by-step explanation: let length of rectangle be l and breadth be b according to question: l=2b+1 and if... breadth is doubled i.e. breadth = 2b and length = l-4 then area remains same (l×b)= (l×b) (2b+1)×b = (2b+1-4)(2b) 2b^2+b = 4b^2-6b 2b^2=7b b^2=3.5b b^2/b=3.5 b = 3.5 l= 2b+1 l= 2×3.5 + 1 l= 8 HOPE it HELPS MARK as BRAINLIEST |
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