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The length of a rectangle is greater than the breadth by 18 cm. If both length andbreadth are increased by 6 cm, then area increases by 168 cm2. Find the lengthand breadth of the rectangle. |
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Answer» Let the breadth of the rectangle be x. Then the length of the rectangle will be greater than the breadth by 18cm = (x+18) cm. We know that Area of the rectangle = l * b = x * (x + 18) = x^2 + 18x ------------- (1) Given that breadth of the rectangle is increased by 6cm. = (x+6)cm. Then the length of the rectangle = (x + 6 + 18) = (x + 24). Now the area of the rectangle = (x + 6)(x + 24)
= x^2 + 30X + 144 ------------ (2) On solving (1) and (2) with the increased area by 168cm^2. x^2 + 18x + 168 = x^2 + 30x + 144 18x + 168 = 30x + 144 12x = 24 x = 2. If the breadth is 2cm Then the length will be (2 + 18) = 20CM. Therefore the length = 20cm and the breadth = 2cm. HOPING THIS WILL HELP YOU PLZ MARK AS BRAINLIEST AND FOLLOW ME |
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