the length of a rectangle is 6m larger than twice times of its breadth

1.	the length of a rectangle is 6m larger than twice times of its breadth .If it's perimeter is 150m .Find its length and breadth
Answer» Given: The length of a rectangle is 6 m larger than TWICE TIMES of its breadth. Perimeter of rectangle is 150 m. ⠀⠀⠀⠀⠀⠀⠀ To find: Length and breadth of rectangle? ⠀⠀⠀⠀⠀⠀⠀ Solution: ⠀⠀⠀⠀⠀⠀⠀ ☯ LET Breadth of rectangle be x m. Therefore, Length of rectangle is (2x + 6) m. ⠀⠀⠀━━━━━━━━━━━━━━━━━━━ $\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(1.6,-0.7)(0,4.2){2}{\sf\large (2x + 6) m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large x m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$ ⠀⠀⠀⠀⠀⠀⠀ $\underline{\bigstar\:\boldsymbol{According\:to\:the\:question\::}}\\ \\$ Perimeter of rectangle is 150 m. ⠀⠀⠀⠀⠀⠀⠀ $\dag\;{\underline{\frak{As\;we\;know\;that,}}}\\ \\$ $\star\;{\boxed{\sf{\pink{Perimeter_{\;(rectangle)} = 2(length + breadth)}}}}\\ \\$ $\dag\;{\underline{\frak{Putting\;values\;in\;formula,}}}\\ \\$ $:\implies\sf 2[(2x + 6) + x] = 150\\ \\$ $:\implies\sf 2[3x + 6] = 150\\ \\$ $:\implies\sf 3x + 6 = \cancel{ \dfrac{150}{2}}\\ \\$ $:\implies\sf 3x + 6 = 75\\ \\$ $:\implies\sf 3x = 75 - 6\\ \\$ $:\implies\sf 3x = 69\\ \\$ $:\implies\sf x = \cancel{ \dfrac{69}{3}}\\ \\$ $:\implies{\underline{\boxed{\frak{\purple{x = <klux>23</klux>}}}}}\;\bigstar\\ \\$ Therefore, ⠀⠀⠀⠀⠀⠀⠀ Length of Rectangle, x = 23 m Breadth of Rectangle, (2x + 6) = 46 + 6 = 52 m ⠀⠀⠀━━━━━━━━━━━━━━━━━━━ $\qquad\qquad\boxed{\underline{\underline{\pink{\bigstar \: \bf\:More\:to\:know\:\bigstar}}}} \\ \\$ Area of Rectangle = Length × Breadth Diagonal of Rectangle = √(length)² + (breadth)² Area of square = SIDE × side Perimeter of square = 4 × side Diagonal of square = √2 × side

the length of a rectangle is 6m larger than twice times of its breadth .If it's perimeter is 150m .Find its length and breadth

Answer»

Given:

The length of a rectangle is 6 m larger than TWICE TIMES of its breadth.
Perimeter of rectangle is 150 m.

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To find:

Length and breadth of rectangle?

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Solution:

⠀⠀⠀⠀⠀⠀⠀

☯ LET Breadth of rectangle be x m.

Therefore, Length of rectangle is (2x + 6) m.

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$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(1.6,-0.7)(0,4.2){2}{\sf\large (2x + 6) m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large x m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$