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The length of a given cylindrical wire is increased by `100%`. Due to the consequent decrease in diameter the change in the resistance of the wire will beA. `200 %`B. `100 %`C. `50%`D. `300%` |
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Answer» Correct Answer - D `R=rho l/A=rho(l^(2))/Vimplies R prop l^(2)` `as l to2l` `impliesR to 4R` `implies %` change in `R=300 %` |
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