the length breadth and height of a room are 9m,14m and 15m respectivel

1.	the length breadth and height of a room are 9m,14m and 15m respectively find the cost of white washing the four wall of the room at the rate of ruppes 12 per meter square
Answer» $\sf{\underline{Given}}$ Length of the room = 9 m Breadth of the room = 14 m Height of the room = 15 m $\sf{\underline{To\:Find}}$ The cost of white-washing the four walls at the RATE of Rs.12 per m² $\sf{\underline{Solution}}$ 11 Length of the room = 9 m Breadth of the room = 14 m Height of the room = 15 m $\sf{Area\:of\:four\:walls = 2(Length+Breadth)\times Height\:\:sq.units}$ = $\sf{Area = 2(9+14)\times 15\:\:m^2}$ = $\sf{Area = 2\times23\times15\:\:m^2}$ = $\sf{Area = 690\:\:m^2}$ Now, Cost of PAINTING 1 m² = Rs.12 $\sf{Cost\:of\:white-washing\:690\:m^2 = 12\times690}$ = $\sf{Cost\:of\:white-washing\:690\:m^2 = 8280}$ Therefore cost of white-washing the four walls of the room is Rs.8280. _________________________________________ $\sf{\underline{More\:Information}}$ $\sf{Volume\:of\:a\:cuboid = (Length\times Breadth\times Height)\:cubic\:units}$ $\sf{TSA\:of\:a\:cuboid = 2(LB + BH + HL)\:sq.units}$ $\sf{LSA\:of\:cuboid = 2(L+B)\times H\:\:units}$ $\sf{\underline{Note}}$ L = Length B = Breadth H = Height LSA = LATERAL surface area (ALSO known as Area of four walls) TSA = Total Surface Area. _________________________________________