The length, breadth and height of a rectangular block are found to be 15.12 pm 0.02cm, 7.86 pm 0.01cm" and "4.16 pm 0.02cm, respectively. Compute the percentage error in the volume of the block.

The length, breadth and height of a rectangular block are found to be

1.	The length, breadth and height of a rectangular block are found to be 15.12 pm 0.02cm, 7.86 pm 0.01cm" and "4.16 pm 0.02cm, respectively. Compute the percentage error in the volume of the block.
Answer» Solution :Given, length, `l= 15.12 pm 0.02 cm` Breadth, `b= 7.86 pm 0.01cm` Height, `h= 4.16 pm 0.02 cm` VOLUME of rectangular BLOCK is `V= l xx b xx h` The percentage error in the volume is given by `(triangle V)/(V)xx100= ((trianglel)/(l)+(TRIANGLEB)/(b)+(triangleh)/(h))xx100` `=((0.02)/(15.12)+(0.01)/(7.86)+(0.02)/(4.16))xx100` `=((2)/(1512)+(1)/(786)+(2)/(416))xx100` `=0.1323+0.1272+0.4808= 0.7403%` `=0.74%` (Rounded off to 2 SIGNIFICANT figures).