the Length breadth and height a rectangular block of wood when measure

1.	the Length breadth and height a rectangular block of wood when measured to be l equals to 12. 13 plus minus 0.02 CM B equals to 8.16 plus minus 0.01 CM equals to 3.46 plus minus 0.01 CM determine the percentage error in the volume of the block
Answer» Answer: The PERCENTAGE error in the volume of the block is 0.011% EXPLANATION: According to the PROBLEM the length of the rectangular block is l l= 12.13(+-)0.02cm BREADTH of the rectangular block is b b= 8.16(+--)0.01cm height of the rectangular block is h h= 3.46(+-)0.01 cm therefore the volume will be, v= lbh =(12.13+0.02)(8.16+0.01)(3.46+0.01) =342.47+0.04 cm^3 Percentage error can be find subtracting theoritical RESULT with from the experimental. therefore, %error= (Vexperimental−Vtheoritical)/Vtheoritical =342.47−(342.47+0.04)/(342.47+0.04) =0.011%

the Length breadth and height a rectangular block of wood when measured to be l equals to 12. 13 plus minus 0.02 CM B equals to 8.16 plus minus 0.01 CM equals to 3.46 plus minus 0.01 CM determine the percentage error in the volume of the block

Answer»

Answer:

The PERCENTAGE error in the volume of the block is 0.011%

EXPLANATION:

According to the PROBLEM the length of the rectangular block is l

l= 12.13(+-)0.02cm

BREADTH of the rectangular block is b

b= 8.16(+--)0.01cm

height of the rectangular block is h

h= 3.46(+-)0.01 cm

therefore the volume will be,

v= lbh =(12.13+0.02)(8.16+0.01)(3.46+0.01)

=342.47+0.04 cm^3

Percentage error can be find subtracting theoritical RESULT with from the experimental.

therefore,

%error= (Vexperimental−Vtheoritical)/Vtheoritical

=342.47−(342.47+0.04)/(342.47+0.04)

=0.011%

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