the length and width of a rectangle are in the ratio 5:3 .Find the dim

1.	the length and width of a rectangle are in the ratio 5:3 .Find the dimenisions of the rectangle, if its perimeter is 122 cm .
Answer» Answer: THIS IS YOUR ANSWER PLEASE MARK IT AS BRAINLEST Step-by-step explanation: Answer: The Length is 35 CM and Breadth is 15 cm. Step-by-step explanation: GIVEN : Ratio of Length to Breadth = 5 : 3 PERIMETER of the rectangle = 112 cm To find : The dimensions of the rectangle Solution : Let the - Length be 5y Bredth be 3y ★ Perimeter = 2(Length + Breadth) ⇒ 112 = 2(5y + 3y) ⇒ 112 = 10y + 6y ⇒ 112 = 16y ⇒ y = 112/16 ⇒ y = 7 $$\rule{300}{1.5}$$ ★ Value of 5(y) ⇒ 5(7) ⇒ 35 Length = 35 cm $$\rule{300}{1.5}$$ ★ Value of 3y ⇒ 3(5) ⇒ 15 Breadth = 15 cm $$\therefore$$ The Length is 35 cm and Breadth is 15 cm.

the length and width of a rectangle are in the ratio 5:3 .Find the dimenisions of the rectangle, if its perimeter is 122 cm .

Answer»

Answer:

THIS IS YOUR ANSWER PLEASE MARK IT AS BRAINLEST

Step-by-step explanation:

Answer:

The Length is 35 CM and Breadth is 15 cm.

Step-by-step explanation:

Ratio of Length to Breadth = 5 : 3

PERIMETER of the rectangle = 112 cm

To find :

The dimensions of the rectangle

Solution :

Let the -

Length be 5y

Bredth be 3y

★ Perimeter = 2(Length + Breadth)

⇒ 112 = 2(5y + 3y)

⇒ 112 = 10y + 6y

⇒ 112 = 16y

⇒ y = 112/16

⇒ y = 7

$$\rule{300}{1.5}$$

★ Value of 5(y)

⇒ 5(7)

⇒ 35

Length = 35 cm

$$\rule{300}{1.5}$$

★ Value of 3y

⇒ 3(5)

⇒ 15

Breadth = 15 cm

$$\therefore$$ The Length is 35 cm and Breadth is 15 cm.