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The length and breadth of a rectangular sheet are 16.2 cm and 10.1 cm, respectively. The area of the sheet in appropriate significant figures and error is (A) 164 + 3 cm2 (B) 163.62 £ 2.6 cm2 (C) 163.6 + 2.6 cm2 (D) 163.62 + 3 cm.any one please ans me fast |
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Answer» Given Length and breadth of a rectangular sheet are 16.2 cm and 10.1 CM respectively the AREA of the sheet in APPROPRIATE significant figures and error is Let Δa = error in measurement of a Δb = error in measurement of b Δx = error in finding x Now maximum fractional error in x is So Δx /x = (Δa/a + Δb/b) Now given length = (16. cm^2 ± 0.1) cm Breadth = b = (10.1 ± 0.1) cm Area = L x b = 16.2 x 10.1 = 163.62 sq cm Now rounding off the area we get area = 164 sq cm If ΔA is error in area, then RELATIVE error is given as ΔA/A = Δl/l ± Δb/b = 0.1/16.2 ± 0.1/10.1 = 1.01 ± 1.62 / 163.62 = 2.63 / 163.62 It implies ΔA = A x 2.63 / 163.62 sq cm = 163.62 x 2.63 / 163.62 = 2.63 sq cm By rounding off to one significant FIGURE we get ΔA = 3 sq cm Now Area = A ± ΔA = (164 ± 3) sq cm please mark me brain mark list |
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