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The least distance of the line `8x -4y+73=0` from the circle `16x^2+16y^2+48x-8y-43=0` is |
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Answer» Correct Answer - `2sqrt(5)` `16x^(2)+16y^(2)+48x-8y-43=0` or `x^(2)+y^(2)+3x-(1)/(2)y-(43)/(16)=0` Center of the circle `: (-(3)/(2),(1)/(4))` Radius`= sqrt((9)/(4)+(1)/(16)+(43)/(16))=sqrt(5)` Required least distance `=` Distance of line from centre of circle `-` Radius of circle `= (|8(-(3)/(2))-4((1)/(4))+73|)/(sqrt(64+16))-sqrt(5)` `=(60)/(4 sqrt(5))-sqrt(5)= 2 sqrt(5)` |
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