The least count of stop watch is 0.5s. The time of 40 oscillation of the pendulum is found to be 40s. The percentage error in the measurement of time period is ……………… %

The least count of stop watch is 0.5s. The time of 40 oscillation of t

1.	The least count of stop watch is 0.5s. The time of 40 oscillation of the pendulum is found to be 40s. The percentage error in the measurement of time period is ……………… %
Answer» 0.75 0.5 1.25 0.25 Solution :`"Least COUNT = 0.5a"` `DELTAT=0.5a` `T=40` `%" ERROR "=(DeltaT)/(T)xx100` `=(0.5)/(40)xx100=(50)/(40)=1.25`