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The Laplace transforms of e^-5t |
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Answer» As we all KNOW that, L { f(t) } = F(s) L { t*f(t) } = -d( F(s) )/dt f(t) = e^-5t then Laplace TRANSFORM is F(s) = 1/(s+5) t*f(t) = t*e^-5t then the Laplace transform is -d{ 1/(s+5) }/dt L { t*f(t) } = 1/(s+5)². |
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