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The label on a ceiling lighting fixture warns you to use a lightbulb of 60 watts or less. The voltage to the lightbulb is 120 volts. An intern calculated how much amperage a bulb of the maximum allowed wattage will draw. You are checking her work, shown below. If there is an error, what is the first step that has an error, and why is it an error? |
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Answer» The bulb will draw 0.5 amperes of current when the power is maximum. Step-by-step explanation: Actual CALCULATION : Given: Voltage, V = 120 volts Maximum power, P = 60 watt To find: Current, I = ? We KNOW, Power = Voltage * Current Substituting the given values in the above FORMULA, 60 = 120 * I I = 60/120 = 0.5 Amp Hence, the bulb will draw 0.5 amperes of current when the power is maximum. |
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