1.

The K.E. of one mole of a gas at normal temperature and pressure is(a) 0.56 x 104 J(b) 1.3 x 102J(c) 2.7 x 102J(d) 3.4 x 103J

Answer»

(d) 3.4 x 103J

K . E  = \(\frac{3}{2}\)RT = \(\frac{3}{2}\) x 8.31 x 273

= 3.4 x 103J



Discussion

No Comment Found