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The ions from among the following which are colourless are `:` `(i)Ti^(+4)" "(ii)Cu^(+1)" "(iii)Co^(+3)" "(iv)Fe^(+2)`A. (i) and (ii) onlyB. (i),(ii) and (iii)C. (iii) and (iv)D. (ii) and (iii) |
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Answer» Correct Answer - A (i)Valance shell electron configuration of `Ti^(4+)` is `3d^@ 4s^@`.As there is no unpaired electrons for d-d transition. The solution of ions will be colourless. (ii)Valance shell electron configuration of `Cu^(+)` is `3d^10 4s^@`.As electrons are paired, there is no d-d transition, so the solution of ions will be colourless. (iii)Valance shell electron configuration of `Co^(3+)` is `3d^6 4s^@`.As there are 4 unpaired electrons for d-d transition of electron, so The solution of ions will be coloured. (iv)Valance shell electron configuration of `Fe^(2+)` is `3d^6 4s^@`.As there are 4 unpaired electrons there is d-d transition. The solution of ions will be coloured. |
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