Saved Bookmarks
| 1. |
The ionization potential for the electron in the ground state of hydrogen atom is 13.6 eV. Whatwould be the ionization potential for the electron inthe first excited state of Li2+?(1) 54.4 eV(2) 5.4 eV(3) 30.6 eV(4) 84.4 eV |
| Answer» IE = 13.6evdelta E =13.6z^2(1/n1^2 - 1/n2^2)delta E = 30.6 eV( as VALUE of z=3, n1= 2 and n2= INFINITY)hope it helps | |