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The ionization enthalpy of Na+ formation from Na(g) is 495.8 kJmol−1, while the electron gain enthalpy of Br is −325.0 kJmol−1. Given the lattice enthalpy of NaBr is −728.4 kJmol−1. The energy for the formation of NaBr ionic solid from Na(g) and Br(g) is (-)__________ ×10−1kJmol−1

Answer» The ionization enthalpy of Na+ formation from Na(g) is 495.8 kJmol1, while the electron gain enthalpy of Br is 325.0 kJmol1. Given the lattice enthalpy of NaBr is 728.4 kJmol1. The energy for the formation of NaBr ionic solid from Na(g) and Br(g) is (-)__________ ×101kJmol1


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