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The ionization energy of hydrogen atom is X KJ. The energy required for an electron to jump from 2nd orbit to the 3rd orbit will be...... |
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Answer» ONG>ANSWER: Ionisation ENERGY = E = -E0 / n2 , where E0 = 13.6 eV (1 eV = 1.602×10-19 Joules) and n = 1,2,3… and so on. |
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