The ionization constant of HF, HCOOH and HCN at 298K are 6.8×10–4,1 – InterviewSolution

1.	The ionization constant of HF, HCOOH and HCN at 298K are 6.8×10–4,1.8×10–4 and 4.8×10–9 respectively. Calculate the ionization constants of the corresponding conjugate base.
Answer» The ionization constant of HF, HCOOH and HCN at 298K are $6.8 \times 10^{- 4}, 1.8 \times 10^{- 4}$ and $4.8 \times 10^{- 9}$ respectively. Calculate the ionization constants of the corresponding conjugate base.

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