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The ionization constant of a weak electrolyte is `2.5 xx 10^(-5)`, while of the equivalent conductance of its `0.1 M` solution is `19.6 s cm^(2) eq^(-1)`. The equivalent conductance of the electrolyte at infinite dilution is :A. 250B. 196C. 392D. 386 |
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Answer» Correct Answer - C `K_(a)=Calpha^(2)rArr25xx10^(-6)=10^(-2)xxalpha^(2)` `alpha=5xx10^(-2)` `alpha(lamda_(m))/(lamda_(m)^(oo))rArr5xx10^(-2)=(19.6)/(lamda_(m)^(oo))=(19.6xx100)/(8)=392` |
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