1.

The internal energy change (in J) when 90g of water undergoes complete evaporation at 100ºC is ....(Given :ΔHvap for water at 373 K = 41 kJ/mol, R = 8.314 JK–1 mol–1)

Answer»

H2O(l) ⇌ H2O(g)      90 gm of H2

ΔH = ΔU +  ΔngRT  ⇒  5 moles of H2O

5 × 41000 J =  ΔU + 1 × 8.314 × 373 × 5

ΔU = 189494.39 Joule



Discussion

No Comment Found

Related InterviewSolutions