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The internal energy change (in J) when 90g of water undergoes complete evaporation at 100ºC is ....(Given :ΔHvap for water at 373 K = 41 kJ/mol, R = 8.314 JK–1 mol–1) |
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Answer» H2O(l) ⇌ H2O(g) 90 gm of H2O ΔH = ΔU + ΔngRT ⇒ 5 moles of H2O 5 × 41000 J = ΔU + 1 × 8.314 × 373 × 5 ΔU = 189494.39 Joule |
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