The interior angles of a pentagon are in the ratio of 5:4:7:5:6.Find e

1.	The interior angles of a pentagon are in the ratio of 5:4:7:5:6.Find each angle of the pentagon.
Answer» Let them be x : 5X 4x 7x 5x 6X Step-by-step explanation: Now sum of the ANGLES of pentagon = 540 so, 5x+4x+7x+5x+6x =540 27x= 540 x = 540÷27 x= 20 so, 1st ANGLE = 5x = 5×20 = 100 2nd angle= 4x= 4×20 = 80 3rd angle= 7x= 7×20 = 140 4th angle= 5x = 5×20 = 100 5th angle= 6x = 6×20 = 120 then, sum of all angle = 540 100+80+140+100+120 = 540

The interior angles of a pentagon are in the ratio of 5:4:7:5:6.Find each angle of the pentagon.

Answer»

Let them be x :

Step-by-step explanation:

Now

sum of the ANGLES of pentagon = 540

so,

5x+4x+7x+5x+6x =540

27x= 540

x = 540÷27

x= 20

so,

1st ANGLE = 5x = 5×20

= 100

2nd angle= 4x= 4×20

= 80

3rd angle= 7x= 7×20

= 140

4th angle= 5x = 5×20

= 100

5th angle= 6x = 6×20

= 120

then,

sum of all angle = 540

100+80+140+100+120 = 540

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The interior angles of a pentagon are in the ratio of 5:4:7:5:6.Find each angle of the pentagon.​

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The interior angles of a pentagon are in the ratio of 5:4:7:5:6.Find each angle of the pentagon.