The interior angle of regular polygon is four times it's exterior angl

1.	The interior angle of regular polygon is four times it's exterior angle find the sum of interior angle
Answer» Answer: hope it helps Step-by-step explanation: The SUM of the INTERIOR angles of a polygon is four times the sum of its EXTERIOR angles. The sum of the exterior angles of a polygon is always EQUAL to 360 o . The sum of the interior angles of polygon = 180(n−2) => 180(n−2)=4×360 => n−2=8 => n=10 Number of sides in the polygon = 10

The interior angle of regular polygon is four times it's exterior angle find the sum of interior angle

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Answer:

hope it helps

Step-by-step explanation:

The SUM of the INTERIOR angles of a polygon is four times the sum of its EXTERIOR angles.

The sum of the exterior angles of a polygon is always EQUAL to 360

The sum of the interior angles of polygon = 180(n−2)

=> 180(n−2)=4×360

=> n−2=8

=> n=10

Number of sides in the polygon = 10

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The interior angle of regular polygon is four times it's exterior angle find the sum of interior angle

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