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The instantaneous magnetic flux associated with a closed loop of resistance 10 Ω is given by, ϕ=6t2−5t+1, then the magnitude of induced current at t=0.25 s will be - |
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Answer» The instantaneous magnetic flux associated with a closed loop of resistance 10 Ω is given by, ϕ=6t2−5t+1, then the magnitude of induced current at t=0.25 s will be - |
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