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The instantaneous angular position of a particle undergoing a circular motion is given by the equation θ(t)=4t3−3t2. Find the time when the angular acceleration of the particle becomes zero. |
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Answer» The instantaneous angular position of a particle undergoing a circular motion is given by the equation θ(t)=4t3−3t2. Find the time when the angular acceleration of the particle becomes zero. |
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