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The inner diameter of a cylindrical wooden pipe is 24 cm and its outer di28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm of wooa mass of 0.6 g.ameter ishas |
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Answer» Step-by-step explanation: to find mass we have to find volume of pipe Volume of pipe = volume of outer cylinder - volume of inner cylinder Outer cylinder Radius of outer cylinder, r₁ = D/2 28 / 2 = 14 cm height = 35 cm Volume of outer cylinder = πr₁²h = π (14)² 35 Inner cylinder Radius of inner cylinder r₂ = D / 2 = 24 /2 = 12 cm height = 35 cm Volume of inner cylinder= πr₂²h =π (12)²35 So, the volume of pipe = volume of outer cylinder - volume inner cylinder =π (35) (14² - 12²) =22/7 × 35 ( 196 - 144) = 5720 cm³ Mass of 1 cm is 0.6 gm ∴ mass of 5720 cm = 5720 × 0.6 gm = 5720 × 0.6 /1000 kg = 3.432 kg |
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