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The initial velocity of a particle is 10m/s. It is moving with an acceleration of 4m/s^2. The distance covered by the particle after 2 sec is:1. 6m 2.18m 3.22m 4.28m |
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Answer» Answer: u=10m/s a=−2m/s 2
n=5 The DISTANCE covered by the PARTICLE in n th second is S n
=u+ 2 a
(2n−1) S 5
=10− 2 2
(2×5−1) S 5
=10−9=1m |
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