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the initial velocity of a body moving with uniform acceleration of 10m/s2 is 5 m/s what will be the distance coerced at 10 sec |
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Answer» ________________________________________________________→Given that , ◾Initial velocity U = 5 m/s ◾Acceleration a = 10 m/s²◾Time = 10 seconds. => DISTANCE covered S = ? ⭐Using the second equation of Motion , => S = ut + ½ at²•°• Plug in the values - => S = 5 × 10 + ½ × 10 × (10)²=> S = 550 m°•° Distance covered at the end of 10TH second is 550 m ________________________________________________ |
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