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The initial state of a certain gas is (P_i,V_i,T_i). It undergoes expansion till its volume becomes V_f Consider the following two cases : (a) the expansion takes place at constant temperature. (b) the expansion takes place at constant pressure. Plot the P-V diagram for each case. In which of the two cases, is the work done by the gas more ? |
Answer» Solution :The situation is shown in the GIVEN P `to`V graph where variation is shown for each PROCESS. Process 1 is isobaric and process 2 is isothermal. SINCE work done is EQUAL to the area under the P`to`V CURVE, here area under the P `to`V curve 1 is more, so work done is more in isobaric process. |
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