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the incircle of ∆ABC touches the sides AB, BC,,CA respectively at P,Q and R.If AB=14,BC=11 and CA=7 then find AP |
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Answer» Step-by-step EXPLANATION: Answer adi5166 In2 triangle ABC, we have BP= BQ = 3cm AP= AR = 4cm ( TANGENTS DRAWN from an external point to the circle are equal). So, RC = AC-AR =11-4=7cm Hence RC= CQ= 7 cm Then, BC= BQ+QC 7+3=10cm |
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