1.

The hysteresis loop for a certain magnetic material is drawn to the following scales : 1 cm = 200 AT/m and 1 cm = 0.1 Wb/m2. The area of the loop is 48cm2 . Assuming the density of the material to be 7.8 × 103kg/m3 , calculate the hysteresis loss in watt/kg at 50 Hz.

Answer»

Hysteresis loss = xy (area of B/H loop) J/m3 /cycle

Now, 1 cm = 200 AT/m ; 1 cm = 0.1 Wb/m2

∴ x = 200, y = 0.1, area of loop = 48 cm2

∴ loss = 200 × 0.1 × 48 = 960 J/m3 /cycles, Density = 7.8 × 102 kg/m2 

Volume of 1 kg of material = mass/density = 1/7.8 × 103m3 

∴ loss = 960 × 1/7.8 × 103J/cycle No. of reversals/second = 50 

∴ loss = 960 × 50 × 10−3/7.8 = 6.15 J/s or watt 

∴ hysteresis loss = 6.15 watt/kg.



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