The hypotenuse of right angled triangle with its base and perpendicula

1.	The hypotenuse of right angled triangle with its base and perpendicular oflengths 3x, 4x respectively is: *25x7x5xO 16x
Answer» Given : Length of the Base of Triangle is 3x Perpendicular Length of Triangle is 4x To Find : HYPOTENUSE of RIGHT Angled Triangle. Solution : $\setlength{\unitlength}{1.9cm}\begin{picture}(6,2)\linethickness{0.5mm}\put(7.7,2.9){\large\sf{A}}\put(7.7,1){\large\sf{B}}\put(10.6,1){\large\sf{C}}\put(8,1){\line(1,0){2.5}}\put(8,1){\line(0,2){1.9}}\qbezier(10.5,1)(10,1.4)(8,2.9)\put(8.6,0.7){\sf{\large{3 x}}}\put(8.2,1){\line(0,1){0.2}}\put(8,1.2){\line(3,0){0.2}}\put(7.4,1.8){\sf 4 x}\put(9.4,2.2){\sf ? }\end{picture}$ Using Pythagoras Theoram : $\longmapsto\tt\bf{{(H)}^{2}={(B)}^{2}+{(P)}^{2}}$ $\longmapsto\tt{{H}^{2}={3x}^{2}+{4x}^{2}}$ $\longmapsto\tt{{H}^{2}={9x}^{2}+{16x}^{2}}$ $\longmapsto\tt{{H}^{2}=25{x}^{2}}$ $\longmapsto\tt{H=\sqrt{25{x}^{2}}}$ $\longmapsto\tt\bf{H=5x}$ So , The Hypotenuse of the Triangle is 5x...

The hypotenuse of right angled triangle with its base and perpendicular oflengths 3x, 4x respectively is: *25x7x5xO 16x

Answer»

Given :

Length of the Base of Triangle is 3x
Perpendicular Length of Triangle is 4x

To Find :

HYPOTENUSE of RIGHT Angled Triangle.

Solution :

$\setlength{\unitlength}{1.9cm}\begin{picture}(6,2)\linethickness{0.5mm}\put(7.7,2.9){\large\sf{A}}\put(7.7,1){\large\sf{B}}\put(10.6,1){\large\sf{C}}\put(8,1){\line(1,0){2.5}}\put(8,1){\line(0,2){1.9}}\qbezier(10.5,1)(10,1.4)(8,2.9)\put(8.6,0.7){\sf{\large{3 x}}}\put(8.2,1){\line(0,1){0.2}}\put(8,1.2){\line(3,0){0.2}}\put(7.4,1.8){\sf 4 x}\put(9.4,2.2){\sf ? }\end{picture}$