1.

The hydrogen electrode is dipped in a solutionof pH = 3 at 25°C. The potential of the cellwould be(use value of 2.303RT/F=0.059v)= 0.059 V(a) 0.059 V(c) 0.178 V(b) 0.088 V(d)-0.177 V​

Answer»

Answer:

Option D -0.177 V,

Explanation:

⇒pH=3,

⇒[H3O^+]=10^-pH=10^-3M,

⇒E el=E el^0-0.059/n LOG PH2/[H^+]^2,

⇒E el=0-0.059/n log 1/(10^-3)^2,

⇒E el=-0.177 V.

Hope it helps you.


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