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The hydraulic press shown in the figure is used to raise the mass M through a height of `0.5 cm` by performing `500J` of work at the small piston. The diameter of the large piston is `10cm`, while that of the smaller one is `2 cm`. The mass M is A. `100kg`B. `10^(6)kg`C. `10^(3)kg`D. None of these |
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Answer» Correct Answer - D Diameter of left hand side is `(1)/(5)` times. So area will be `(1)/(25)` times. `Deltap_(LHS) =Delta p_(RHS)implies (F)/((A//25))=((Mg))/(A)` `:. F=(Mg)/(A)` Equating the volumes Displacement of `LHS=5` times Displacement of RHS `:. S=(5)(0.5)=2.5cm` `:. (500)=((Mg)/(25))(2.5xx10^(-2))` `:. M=5xx10^(4)kg` (with `g=10m//s^(2)`. |
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