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The hybridization of atomic orbitals of nitrogen is `NO_(2)^(+), NO_(3)^(-)`, and `NH_(4)^(+)` respectively areA. `sp,sp^(3),and sp^(2)` respectivelyB. `sp,sp^(2),and sp^(3)` respectivelyC. `sp^(2),sp,and sp^(3)` rspectivelyD. `sp^(2),sp^(3),and sp` respectively |
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Answer» Correct Answer - B `NO_(2)^(+)=1//2[5+0-1+0]=4//2=sp` `NO_(3)^(-)=1//2[5+0-0+1]=6//2=sp^(2)` `NH_(4)^(+)=1//2[5+4-1+0]=8//4=sp^(3)` |
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