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The hour and minute hands of a clock are 4 cm and 6 cm long respectively. Find the sum of the distances travelled by their tips in 2 days. |
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Answer» Length of the hour hand is 4 cm, which describes the radius of the path inscribed by the hour hand. Length of the minute hand is 6 cm, which describes the radius of the path inscribed by the minute hand. The circumference of the path inscribed by the hour hand = 2 π r C = 2 × (22/7) × 4 C = 176/7 cm The hour hand makes 2 revolutions in one day. Therefore distance covered by the hour hand in 2 days = (176/7) × 2 × 2 = 100.57 cm The distance covered by the minute hand in 1 revolution = 2 π r C = 2 × (22/7) × 6 C = 264/7 As we know, the minute hand makes 1 revolution in one hour. In 1 day, it makes 24 revolutions. In 2 days, it makes 2 × 24 revolutions. The distance covered by the minute hand in 2 days = 2 × 24 × (264/7) = 12672/7 = 1810.28 cm The sum of the distances travelled by the hour and minute hands in 2 days = 1810.28 + 100.57 = 1910.85 cm |
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