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The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile isA. `theta = tan^(-1) ((1)/(4))`B. `theta = tan^(-1)(4)`C. `theta = tan^(-1)(2)`D. `theta = 45^(@)` |
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Answer» Correct Answer - B Given, `R = H` Range, `R = (u^(2)(2 sin theta cos theta))/(g)` Height, `H = (u^(2)sin^(2)theta)/(2g)` Hence, `(u^(2)(2sin theta cos theta))/(g) = (u^(2)sin^(2)a)/(2g)` `2 cos theta = (sin theta)/(2) rArr tan theta = 4 rArr theta = tan^(-1)(4)` |
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