The height y and the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmospehre) are given by y=(8t-5t^(2)) metre and x=6t metre, where t is in seconds. The velocity of projection is:

The height y and the distance x along the horizontal plane of a projec

1.	The height y and the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmospehre) are given by y=(8t-5t^(2)) metre and x=6t metre, where t is in seconds. The velocity of projection is:
Answer» 8m/s 6m/s 10m/s not obtianed from the data Solution :`y=(u_(x))/(3)-(5X^(2))/(36)` Now, `y=x tan THETA-(gx^(2))/(2U^(2)cos^(2)theta)` `U=10m//s`