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The height y and distance x along the horizontal plane of a projectile on a certain planet are given y=8t−5t2 (mtr) and x=6t (mtr). The acceleration due to gravity is: |
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Answer» The height y and distance x along the horizontal plane of a projectile on a certain planet are given y=8t−5t2 (mtr) and x=6t (mtr). The acceleration due to gravity is: |
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