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The height of a solid cone is 12 cm and the area of the circular base is 64π cm2. A plane parallel to the base of the cone cuts through the cone 9 cm above the vertex of the cone, the area of the base of the new cone so formed is :A. 9π cm2 B. 16π cm2 C. 25π cm2 D. 36π cm2 |
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Answer» Option : (D) We have, Height of cone = 12cm Area of circular base = 64π cm2 Height from the vertex of small cone = 9 cm πr2 = 64π r2= 64 Radius of base = 8cm From similarity triangle = \(\frac{12}{8}\) = \(\frac{9}{R}\) = R = \(\frac{9\times8}{12}\) = 6 cm R = radius of small cone Area of small cone = πr2 = π(6)2 = 36π cm2 |
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