1.

The height of a solid cone is 12 cm and the area of the circular base is 64π cm2. A plane parallel to the base of the cone cuts through the cone 9 cm above the vertex of the cone, the area of the base of the new cone so formed is :A. 9π cm2 B. 16π cm2 C. 25π cm2 D. 36π cm2

Answer»

Option : (D)

We have, 

Height of cone = 12cm 

Area of circular base = 64π cm2 

Height from the vertex of small cone = 9 cm 

πr2 = 64π 

r2= 64 

Radius of base = 8cm 

From similarity triangle = \(\frac{12}{8}\) = \(\frac{9}{R}\)

= R = \(\frac{9\times8}{12}\) 

= 6 cm

R = radius of small cone 

Area of small cone = πr2 

= π(6)2 

= 36π cm2



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