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The heat of neutralization of LiOH and `H_(2)SO_(4)` at `25^(@)`C is `69.6 KJ mol^(-1)`. Calculate the heat of innisation of LiOH will be nearly :-A. `22.5KJmol^(-1)`.B. `90 KJ mol^(-1)`.C. `45KJ mol^(-1)`D. `33.6KJmol^(-1)` |
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Answer» Correct Answer - A `2LiOH+H_(2)SO4toLi_(2)SO_(2)+2H_(2)SO_(4)O` `Delta H_"(neut.)"=-69.6KJ//mol=2DeltaH_(ion)(LiON)+O-57.3xx2` `DeltaH_(ioni(LiOH)=22.5KJ//mol`. |
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