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The heat of atomisation of `PH_(3(g))` is `228kcal mol^(-1)` and that of `P_(2)H_(4)` is `355kcal mol^(-1)`. Calculate the average bond energy of `P-P` bond.A. 63 kcal/molB. 58 kcal/molC. 5 kcal/molD. 45 kcal/mol |
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Answer» Correct Answer - C `PH_(3(g)) rarr P_((g)) + 3H_((g)) Delta H_1 = 228 kcal//mol` `H_2 P - PH_2 rarr 2P + 4H_((g)) Delta H_2 = 355 kcal//mol` `Delta H_2 = E_(p-p) + 4 E_(P-H)` `355 = E_(p-p) + 4 xx (228)/(3)` `E_(P-P) = 51 kcal//mol`. |
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