The heat loss from 100grams of 80 degree Celsius of water is gained by 100grams of 20 degree celsiCelsius of water resulting in a final temperature of 50degree Celsius substitute the values in T=(m1 T1+m2T2)(m1 +m2)

The heat loss from 100grams of 80 degree Celsius of water is gained by

1.	The heat loss from 100grams of 80 degree Celsius of water is gained by 100grams of 20 degree celsiCelsius of water resulting in a final temperature of 50degree Celsius substitute the values in T=(m1 T1+m2T2)(m1 +m2)
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The heat loss from 100grams of 80 degree Celsius of water is gained by 100grams of 20 degree celsiCelsius of water resulting in a final temperature of 50degree Celsius substitute the values in T=(m1 T1+m2T2)(m1 +m2)

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