1.

The heat generated in a circuit is given by Q=I^(2)Rt, where I is current, R is resistance and t is time. If the percentage errors in measuring I,R and t are 2%,1% and 1% respectively, then the maximum error in measuring heat will be :

Answer»

`2%`
`3%`
`4%`
`6%`

Solution :Here `Q=I^(2)Rt`
`:.(dQ)/(Q)XX100=2(DI)/(I)xx100+(dR)/(R)xx100+(DT)/(t)xx100`
`2xx2%+1%+1%`
HENCE `(d)` is correct.


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