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The HCF of two numbers is 27 and their LCM is 162. If one of the numbers is 54, what is the other number? |
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Answer» We know that the product of the numbers is equal to the product of their HCF and LCM. Let the other number is x. Then 54x = 27× 162. (∵ LCM(54, x) = 162 & HCF(54, x) = 27 and one number is 54.) ⇒ x = \(\frac{27\times162}{54}\) = \(\frac{162}{2}\) = 81. Hence, the other number is 81. |
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