1.

The HCF of two numbers is 27 and their LCM is 162. If one of the numbers is 54, what is the other number?

Answer»

We know that the product of the numbers is equal to the product of their HCF and LCM.

Let the other number is x.

Then 54x = 27× 162.

(∵ LCM(54, x) = 162 & HCF(54, x) = 27 and one number is 54.)

⇒ x = \(\frac{27\times162}{54}\) = \(\frac{162}{2}\) = 81.

Hence, the other number is 81.



Discussion

No Comment Found

Related InterviewSolutions