1.

The HCF of two numbers is 27 and their LCM is 162. If one of the number is 81. Then, find the other.

Answer»

Given that HCF of two numbers is 27 and their LCM is 162. 

One number is 81. 

Let the other number is a. 

We know that for two positive integer a & b, HCF (a, b) × LCM (a,b) = a × b.

Therefore, HCF (81, a) × LCM (81, a) = 81 × a

⇒ a = \(\frac{HCF(81,a) \times LCM(81,a)} {81}\)

⇒ a = \(\frac{27 \times 162}{81} = 27 \times 2 = 54.\)

Hence, the other number is 54.



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