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The HCF of two numbers is 27 and their LCM is 162. If one of the number is 81. Then, find the other. |
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Answer» Given that HCF of two numbers is 27 and their LCM is 162. One number is 81. Let the other number is a. We know that for two positive integer a & b, HCF (a, b) × LCM (a,b) = a × b. Therefore, HCF (81, a) × LCM (81, a) = 81 × a ⇒ a = \(\frac{HCF(81,a) \times LCM(81,a)} {81}\) ⇒ a = \(\frac{27 \times 162}{81} = 27 \times 2 = 54.\) Hence, the other number is 54. |
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